Since we know that xcom=∑imixi∑imi, we can say that xcom=−a⋆M⋆+apmpM⋆+mp. Setting xcom=0 allows us to determine that M⋆a⋆=mpap.
b) In a two-body orbital system the variable a is the mean semimajor axis, or the sum of the planet's and star's distances away from their mutual center of mass: a=ap+a⋆. Label this on your diagram. Now derive the relationship between the total mass M⋆+mp≈M⋆, orbital period P, and the mean semimajor axis a, starting with the Virial Theorem for a two-body orbit.
The Virial Theorem states that −12U=K or −12GMmr=12mv2. Since the planet is much smaller than the star, the center of mass will be much closer to the star and therefore a≈ap. This allows us to find the velocity based on the planet's period: v=2πaP.
mp(2πaP)2=GM⋆mpa
4πa2P2=GMa
P2=4π2a3GM
This is Kepler's third law!
c) By how much is the Sun displaced from the Solar System's center of mass as a result of Jupiter's orbit? Express this displacement in a useful unit such as Solar radii. (Potentially useful numbers: M⊙≈1000MJup and ajup≈5.2AU.)
M⋆a⋆=mpap
1000MJupa⊙=MJup5.2AU
a⊙=0.0052AU
0.0052AU11.5×108km1AU1R⊙7.0×105km≈1R⊙: Jupiter displaces the Sun by about one Solar radius.
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